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Geometry · Chapter 23

Angle Chasing

Hunt down a missing angle one clue at a time: straight lines, triangles, parallel lines, polygons and circles all leave footprints.

You'll need

Nothing! This is where it all starts. If you can multiply, you're ready.

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Angle Chasing Basics

In this section you will be able to find a missing angle by chaining simple facts: triangles add to 180°, straight lines add to 180°, and some angles are always equal.

A detective never sees the crime. She follows clues, one at a time, until the answer is cornered. Angle chasing works the same way: each angle you find is a clue to the next.

You only need a few tools. A triangle’s angles add to 180°. Angles on a straight line add to 180°. Opposite angles at a crossing are equal, and so are matching angles on parallel lines.

Look:Whenever two sides of a triangle are equal, two angles are equal too. Hunt for equal sides: radii, square sides, equilateral sides.

Exploreplay first, formulas later

Triangle ABC: 73° + 64° + 43° = 180°

73° + 64° + 43° = 180°

Tip: drag a coloured point, or press Tab to reach it and use the arrow keys.

Angles 73°, 64° and 43°. Sum: 180°.

Name it

Concept 23.1.1 · Angle Chasing Tricks

  • Sum of Angles in Triangle is 180∘180^\circ
  • A triangle with 2 angles equal will have their corresponding sides equal and a triangle with 2 sides equal will have their corresponding angles equal (isosceles triangle)
  • Opposite angles in intersecting lines are equal
  • Corresponding angles in parallel lines are equal
  • The angle made by the arc at the center of the circle is double the angle made by the arc at the boundary of the circle

Concept 23.1.2 · Complementary Angle

Complementary angles are a pair of angles with the sum of 90 degrees:

a+b=90∘a + b = 90^\circ

Concept 23.1.3 · Supplementary Angle

Supplementary angles are a pair of angles with the sum of 180 degrees:

a+b=180∘a + b = 180^\circ

Concept 23.1.4 · Intersecting lines

When two lines intersect, the vertical angles are equal. Vertical angles are each of the pairs of opposite angles made by two intersecting lines. "Vertical" in this case means they share the same Vertex (corner point), not the usual meaning of up-down.

Concept 23.1.5 · Parallel Lines

Corresponding angles equal: when a line crosses two parallel lines, the angles in matching positions at the two crossings are the same.

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Example 23.1

AMC 8

The degree measure of angle AA is

  1. 1

    Find the triangle that has the 40∘40^\circ corner and the 100∘100^\circ angle. Its third corner is the right end of the horizontal line. How big is that corner?

    Predict first:
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Example 23.2

EMCC

In acute △ABC\triangle ABC, D and E are points inside triangle ABC such that DE∥BCDE \parallel BC, BB is closer to DD than it is to EE, ∠AED=80∘\angle AED = 80^\circ, ∠ABD=10∘\angle ABD = 10^\circ, and ∠CBD=40∘\angle CBD = 40^\circ. Find the measure of ∠BAE\angle BAE, in degrees.

  1. 1

    Extend AEAE until it hits BCBC at FF. Line AFAF crosses the parallel lines DEDE and BCBC. Which angle at FF matches ∠AED\angle AED?

    Predict first:
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Try it

Problem 23.5.1

In the adjoining figure, ABCDABCD is a square, ABEABE is an equilateral triangle and point EE is outside square ABCDABCD. What is the measure of ∠AED\angle AED in degrees?

Contest cornerreal contest problems

Problem 23.5.3

AMC 8

In △ABC\triangle ABC, DD is a point on side AC‾\overline{AC} such that BD=DCBD = DC and ∠BCD\angle BCD measures 70∘70^\circ. What is the degree measure of ∠ADB\angle ADB?

Problem 23.5.6

AMC 8

Two angles of an isosceles triangle measure 70∘70^\circ and x∘x^\circ. What is the sum of the different possible values of xx?

Problem 23.5.2

AMC 8

In quadrilateral ABCDABCD, sides AB‾\overline{AB} and BC‾\overline{BC} both have length 10, sides CD‾\overline{CD} and DA‾\overline{DA} both have length 17, and the measure of angle ADCADC is 60∘60^\circ. What is the length of diagonal AC‾\overline{AC}?

Problem 23.5.10(additional)

EMCC

Point PP lies inside triangle ABCABC such that ∠PBC=30∘\angle PBC = 30^\circ and ∠PAC=20∘\angle PAC = 20^\circ. If ∠APB\angle APB is a right angle, find the measure of ∠BCA\angle BCA in degrees.

Problem 23.5.11(additional)

AMC 10/12

As shown in the figure below, point EE lies on the opposite half-plane determined by line CDCD from point AA so that ∠CDE=110∘\angle CDE = 110^\circ. Point FF lies on AD‾\overline{AD} so that DE=DFDE = DF, and ABCDABCD is a square. What is the degree measure of ∠AFE\angle AFE?

Checkpoint for section 23.1

Get 2 of 3 right to master this section. One try each, no hints.
1

Two angles are supplementary. One of them is 47∘47^\circ. How many degrees is the other one?

2

Two parallel lines are cut by a transversal. One of the eight angles is 65∘65^\circ. How many degrees is the largest of the eight angles?

3

In triangle ABC, AB = AC and ∠A=40∘\angle A = 40^\circ. The bisector from ∠B\angle B intersects AC at point D. What is ∠BDC\angle BDC?

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Inscribed Angles

In this section you will be able to use the Inscribed Arc Theorem: an angle on the edge of a circle is half the arc it looks at.

Stand anywhere on the edge of a round stage and look at the two ends of the curtain. Surprise: from every spot on the same side, the curtain fills exactly the same angle of your view!

The angle at the center is always twice the angle on the edge. So every angle on the edge that looks at the same arc is equal, and an angle that looks at a diameter is always 90°.

Look:Regular polygon? Draw a circle through its corners. Equal sides cut the circle into equal arcs.

Exploreplay first, formulas later

Inscribed angle APB = 55°, half of arc AB = 110°

∠APB = 55°

Arc AB (the part not touching P) = 110°. The angle at P is half of it, wherever P sits on the other side.

Inscribed angle APB = 55°. Arc AB = 110°, which is twice as big.

Name it

Theorem 23.2.1 · Inscribed Arc Theorem

The angle formed by an arc in the center or the arc angle is double of the angle formed on the edge.

∠AOB=2 ∠APB\angle AOB = 2\,\angle APB

Every angle on the edge that looks at the same arc is equal.

Remark 23.2.3

A useful trick to solving angle chasing problems with regular polygons is to draw a circle around the polygon and use the inscribed arc theorem.

Corollary 23.2.4 · Inscribed Right Triangle

Inscribed triangle with diameter as one side is always a right triangle. The diameter cuts off an arc of 180∘180^\circ, so the angle opposite it is 180∘2=90∘\frac{180^\circ}{2} = 90^\circ.

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Example 23.3

In regular octagon ABCDEFGH, Find the measure of ∠ACF\angle ACF.

Inscribed angle ACF = 67.5°, half of arc AF = 135°

∠ACF = ?

Arc AF (the part not touching C) = ?. Can you predict the angle before you look?

Inscribed angle ACF: predict it first.

  1. 1

    Draw the circle through all 8 corners. The corners cut it into 8 equal arcs. How many degrees is each arc?

    Predict first:
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Contest cornerreal contest problems

Problem 23.5.5

AMC 8

The circumference of the circle with center OO is divided into 12 equal arcs, marked the letters AA through LL as seen below. What is the number of degrees in the sum of the angles xx and yy?

Problem 23.5.7

AMC 8

Two congruent circles centered at points AA and BB each pass through the other circle's center. The line containing both AA and BB is extended to intersect the circles at points CC and DD. The circles intersect at two points, one of which is EE. What is the degree measure of ∠CED\angle CED?

Checkpoint for section 23.2

Get 2 of 3 right to master this section. One try each, no hints.
1

Points AA, BB and PP lie on a circle with center OO. The central angle ∠AOB\angle AOB is 110∘110^\circ, and PP is on the far side of the circle from arc ABAB. What is ∠APB\angle APB?

2

ABAB is a diameter of a circle and CC is any other point on the circle. What is ∠ACB\angle ACB in degrees?

3

In regular hexagon ABCDEFABCDEF, what is the measure of ∠ACE\angle ACE in degrees?

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Polygons

In this section you will be able to find the angle sum of any polygon and each angle of a regular polygon.

Bees build hexagons, stop signs are octagons, and soccer balls hide pentagons. How big is each corner? You can work it out with triangles.

Draw every diagonal from one corner. An n-sided polygon splits into n − 2 triangles, and each triangle holds 180°.

If you walk around any polygon, you turn one full circle, 360°. In a regular polygon every turn is the same: 360° ÷ n.

Exploreplay first, formulas later

Regular pentagon: interior angles add to (5 − 2) × 180° = 540°, each 108°, each exterior angle 360° ÷ 5 = 72°

sides5
Sum = 540°

Each corner: 540° ÷ 5 = 108°

Walk around the edge. At each corner you turn by the exterior angle.

Regular pentagon: interior angles add to 540°, each 108°. Exterior angle 72°.

Name it

Theorem 23.3.1

Sum of interior angle of a polygon=(n−2)⋅180\text{Sum of interior angle of a polygon} = (n-2)\cdot 180
Interior angle of a regular polygon=(n−2)n⋅180\text{Interior angle of a regular polygon} = \frac{(n-2)}{n}\cdot 180
Exterior angle of a regular polygon=360n\text{Exterior angle of a regular polygon} = \frac{360}{n}

Fact 23.3.2 · Important Interior Angles

Number of sides in regular polygon Interior Angle of regular polygon
3 60
4 90
5 108
6 120
8 135
9 140
10 144

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Example 23.4

MATHCOUNTS

A square is located in the interior of a regular hexagon, and certain vertices are labeled as shown. What is the degree measure of ∠ABC\angle ABC?

  1. 1

    The square shares a side with the hexagon, so all their sides are equally long. What kind of triangle is BCDBCD?

    Predict first:
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Contest cornerreal contest problems

Problem 23.5.8

AMC 10

The keystone arch is an ancient architectural feature. It is composed of congruent isosceles trapezoids fitted together along the non-parallel sides, as shown. The bottom sides of the two end trapezoids are horizontal. In an arch made with 9 trapezoids, let xx be the angle measure in degrees of the larger interior angle of the trapezoid. What is xx?

Problem 23.5.12(additional)

MATHCOUNTS

Concave quadrilateral ABCD is symmetric about the line AC. The measures of angles DAB and ABC are 84 degrees and 32 degrees, respectively. The dashed line segments bisect angles ABC and ADC. What is the degree measure of the acute angle at which the two dashed line segments intersect?

Checkpoint for section 23.3

Get 2 of 3 right to master this section. One try each, no hints.
1

What is the sum of the interior angles of a heptagon (7 sides), in degrees?

2

Each exterior angle of a regular polygon is 24∘24^\circ. How many sides does it have?

3

What is one interior angle of a regular 12-sided polygon, in degrees?

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Advanced Circle Angle Chasing Theorems (Optional)

In this section you will be able to use chords, secants and tangents to turn arcs into angles (optional extras for hard problems).

A bike wheel touches the road at exactly one point. The spoke pointing down to that point always stands straight up from the road. That right angle is a powerful clue.

This section is optional. Each theorem links an angle to the arcs it looks at. Inside the circle you average the arcs. Outside the circle you take half the difference.

Exploreplay first, formulas later

The perpendicular bisectors of chords AB and CD both pass through the centre O

Both dashed bisectors meet at O

Drag A, B, C or D. However you tilt the chords, the dashed lines cross exactly at the centre.

The perpendicular bisectors of AB and CD both pass through the centre O.

Name it

Definition 23.4.1 · Chord

A Chord is a line segment between any two distinct points on the circle. The diameter of the circle is the longest chord in the circle.

Theorem 23.4.2

The perpendicular bisector of any chord passes through the center. In the figure, the perpendicular bisectors of ABAB and CDCD intersect at the center OO.

Corollary 23.4.3

  • Congruent chords are equidistant from the center of a circle.
  • If two chords in a circle are congruent, then their intercepted arcs are congruent.
  • If two chords in a circle are congruent, then they determine two central angles that are congruent.

Theorem 23.4.4

The angle marked in the diagram is half of the difference of the 2 red arcs.

∠APC=BD⌢−AC⌢2\angle APC = \frac{\overset{\frown}{BD} - \overset{\frown}{AC}}{2}

Theorem 23.4.5

If two chords ABAB and CDCD intersect at PP, then the ∠BPC\angle BPC and ∠APD\angle APD are equal to the average of the two arcs.

∠BPC=∠APD=BC⌢+AD⌢2\angle BPC = \angle APD = \frac{\overset{\frown}{BC} + \overset{\frown}{AD}}{2}

Theorem 23.4.6

If a tangent RR intersects the circle at QQ, and a chord QPQP is drawn, then the ∠RQP\angle RQP is equal to half the arc angle.

∠RQP=QP⌢2\angle RQP = \frac{\overset{\frown}{QP}}{2}

Theorem 23.4.7

Equal chords mark out equal arcs.

This basically means that if you have 2 chords of the same length, the sector of the circle they mark out will be equal.

Definition 23.4.8 · Tangent

A tangent is any line from a point external to the circle that just touches the circle.

Theorem 23.4.9 · Right Angle Tangency Point

If you connect the center of a circle to the point where the circle and a line are tangent, they will form a right angle.

Try it

Problem 23.5.4

In the figure, point A is the center of the circle, the measure of angle RAS is 74∘74^\circ, and the measure of angle RTB is 28∘28^\circ. What is the measure of minor arc BR, in degrees?

Checkpoint for section 23.4

Get 2 of 3 right to master this section. One try each, no hints.
1

Chords ABAB and CDCD cross at PP inside a circle. Arc BCBC is 70∘70^\circ and arc ADAD is 110∘110^\circ. What is ∠BPC\angle BPC in degrees?

2

Two secants from a point PP outside a circle cut off a far arc of 150∘150^\circ and a near arc of 40∘40^\circ. What is the angle at PP in degrees?

3

PSPS and PTPT are tangents from a point PP to a circle with center OO, and ∠SPT=50∘\angle SPT = 50^\circ. What is ∠SOT\angle SOT in degrees?

23.5

Practice Problems

In this section you will be able to mix every angle-chasing tool on the hardest contest problems.

Time for the toughest cases. Draw the figure, label every angle you know, and keep chasing. Every problem has three hints if you get stuck.

Want every problem from this chapter on one page? Open the problem set.

Contest cornerreal contest problems

Problem 23.5.13(additional)

EMCC

In triangle ABCABC, ∠BAC\angle BAC is a right angle and ∠ACB\angle ACB measures 34∘34^\circ. Let DD be a point on segment BCBC for which AC=CDAC = CD, and let the angle bisector of ∠CBA\angle CBA intersect line ADAD at EE. What is the measure of ∠BED\angle BED?

Problem 23.5.14(additional)

EMCC

In square ABCD, point E lies on side BC and point F lies on side CD so that triangle AEF is equilateral and inside the square. Point M is the midpoint of segment EF, and P is the point other than E on AE for which PM = FM. The extension of segment PM meets segment CD at Q. What is the measure of ∠CQP\angle CQP, in degrees?